3y^2-7y+1=0

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Solution for 3y^2-7y+1=0 equation: 



3y^2-7y+1=0

a = 3; b = -7; c = +1;
Δ = b2-4ac
Δ = -72-4·3·1
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{37}}{2*3}=\frac{7-\sqrt{37}}{6}
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{37}}{2*3}=\frac{7+\sqrt{37}}{6}
$

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